# Longest Common Sequence Leetcode

We are going to solve a Hard coding Problem longest common sequence leetcode. LeetCode Link of the Problem is HERE. It is one of the most difficult sequence finding tasks on leetcode. We have tried to Solve this in Python3.

#### Question

Given two strings `text1` and `text2`, you have to return the length of their longest common subsequence leetcode. If there is no common subsequence, you have to return 0.

subsequence of a string is a new string generated from the original string with some characters (can be none) deleted without changing the relative order of the remaining characters.

• For example, `"ace"` is a subsequence of `"abcde"`.
• For example, “fbk” is a subsequence of “facebook”
• For example, “abcde” and “ace” have a common subsequence as “ace”

common subsequence of two strings is a subsequence that is common to both strings.

Examples

Input: text1 = “abcde”, text2 = “ace”
Output: 3
Explanation: The longest common subsequence is “ace” and its length is 3.

Input: text1 = “abc”, text2 = “abc”
Output: 3
Explanation: The longest common subsequence is “abc” and its length is 3.

Input: text1 = “abc”, text2 = “def”
Output: 0
Explanation: There is no such common subsequence, so the result is 0.
﻿

Constraints:

• `1 <= text1.length, text2.length <= 1000`
• `text1` and `text2` consist of only lowercase English characters.

#### Solution to longest common sequence leetcode

class Solution(object):
def longestCommonSubsequence(self, s1: str, s2: str) -> int:

• m,n=len(s1),len(s2)
• dp=[[0 for i in range(n)] for j in range(m)]
• for i in range(m):
• for j in range(n):
• if s1[i]==s2[j]:
• if i==0 or j==0:
• dp[i][j]=1
• else:
• dp[i][j]=1+dp[i-1][j-1]
• else:
• dp[i][j]=max(dp[i-1][j] if i>0 else 0,dp[i][j-1] if j>0 else 0)
• return dp[-1][-1]

Runtime: 775 ms, faster than 38.71% of Python3 online submissions for Longest Common Subsequence.

Memory Usage: 22.7 MB, less than 57.29% of Python3 online submissions for Longest Common Subsequence.

longest common sequence leetcode· Time: O ( m n ) O(mn) O(mn) · Space: O ( m n ) O(mn) O(mn)..

Next Challenges:

Longest Palindromic Subsequence

Delete Operation for Two Strings

Shortest Common Supersequence

Maximize Number of Subsequences in a String

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